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Choose (4) numbers from (1) to (15) such that exactly (2) numbers are multiples of (3). How many selections are possible?

Answer and explanation

Correct answer: (450)

From 1 through 15, the multiples of 3 are 3, 6, 9, 12, and 15, so there are 5 multiples. The remaining 10 numbers are not multiples of 3. We need exactly two multiples and exactly two non-multiples in a selection of four. Choose the two multiples in \\(^{5}C_2=10\\) ways and the two non-multiples in \\(^{10}C_2=45\\) ways. By multiplication, the total is \\(^{5}C_2\\times{}^{10}C_2=10\\times45=450\\).

The word exactly is important: selecting three or four multiples would not satisfy the condition. We independently choose the two required groups, and every resulting group of four is counted once. Therefore option B, 450, is correct.

Related tags

MultiplesExactlySelection

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