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How many positive integer solutions does (x_{1}+x_{2}+x_{3}+x_{4}+x_{5}=20) have?

Answer and explanation

Correct answer: 3876

This is a positive-integer solution problem. First assign 1 to each of the five variables; the remaining sum is 15. The number of non-negative integer solutions is \\(\binom{15+5-1}{5-1}=\binom{19}{4}=3876\\). Hence, 3876 is correct. Using \\(\binom{15}{4}\\) would be incorrect because the initial 1 assigned to every variable must be accounted for. Exam tip: for positive integer solutions of a sum of n into r parts, use \\(\binom{n-1}{r-1}\\).

Related tags

CombinationsStars And BarsPositive Integer SolutionsPermutations And CombinationsClass 11 MathematicsMathematicsClass 11 Mcq

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