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Choose (3) numbers from (1) to (12) such that their sum is odd. How many selections are possible?(1) से (12) तक की संख्याओं में से (3) संख्याएं चुननी हैं जिनका योग विषम हो। कितने चयन संभव हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (110)(110)
There are (6) odd and (6) even numbers. For odd sum choose (1) or (3) odd numbers, giving (^{6}C_{1}{}^{6}C_{2}+^{6}C_{3}=110).(6) विषम और (6) सम संख्याएं हैं। विषम योग के लिए (1) या (3) विषम चुनें, संख्या (^{6}C_{1}{}^{6}C_{2}+^{6}C_{3}=110)।
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