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From (13) students, (5) are to be selected, but one fixed student must not be selected. How many ways are possible?

Answer and explanation

Correct answer: 792

Exclude the fixed student first. We then select 5 students from the remaining 12, so the number of selections is \(\binom{12}{5}=792\). Option 924 equals \(\binom{12}{6}\), so it does not apply here. Exam tip: for a person who must not be selected, remove that person and form the combination from the remaining group.

Related tags

CombinationsRestricted SelectionBinomial CoefficientPermutations And CombinationsClass 11 MathematicsMathematicsClass 11 Mcq

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