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Choose (5) numbers from (1) to (15) such that no two are consecutive. How many ways are possible?(1) से (15) तक की संख्याओं में से (5) संख्याएं चुननी हैं, जिनमें कोई दो लगातार न हों। कितने तरीके हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (462)(462)
By the gap method, the count is (^{15-5+1}C_{5}=^{11}C_{5}=462). In such problems identify the gap condition first.अलगाव विधि से संख्या (^{15-5+1}C_{5}=^{11}C_{5}=462)। ऐसी समस्याओं में पहले अंतर की शर्त पहचानें।
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