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A cricket squad has (7) batters and (6) bowlers. A group of (6) players is to be chosen with at least (2) bowlers. How many ways are possible?

Answer and explanation

Correct answer: 1583

There are \(\binom{13}{6}=1716\) ways to choose 6 players from all 13 players. Exclude groups containing 0 or 1 bowler. With 0 bowlers, the number of groups is \(\binom{7}{6}=7\). With 1 bowler, it is \(\binom{6}{1}\binom{7}{5}=6\times21=126\). Hence the required number is \(1716-7-126=1583\). The option 1589 results from an incorrect count of the one-bowler cases. Exam tip: for an “at least” condition, counting by complement is often quicker.

Related tags

CombinationsPermutations And CombinationsAt Least ConditionComplement CountingBinomial CoefficientsMathematicsClass 11 Mcq

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