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How many diagonals are there in a convex polygon with 10 sides?

Answer and explanation

Correct answer: 35

A diagonal joins two non-adjacent vertices. One method is to choose any two of the 10 vertices, giving C(10,2) = 10 × 9 / 2 = 45 pairs. These pairs include the 10 sides, so the number of diagonals is 45 - 10 = 35. Equivalently, from each vertex we can join to 10 - 3 = 7 non-adjacent vertices, giving 10 × 7 = 70, but this counts every diagonal twice, so 70 / 2 = 35. The standard formula n(n - 3)/2 gives the same result: 10 × 7 / 2 = 35. Hence option B is correct; 45 counts sides as well as diagonals.

Related tags

Polygon DiagonalsVertex SelectionCombinationsConvex PolygonPermutations And CombinationsMathematicsClass 11 Mcq

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