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From 7 distinct books, 4 books are to be selected, but two specified books cannot be selected together. How many selections are possible?

Answer and explanation

Correct answer: 25

Since a selection is an unordered collection, combinations are used. First count all ways to choose 4 books from 7: C(7,4) = 35. Now count the forbidden selections containing both specified books. Once those two books are included, the remaining 2 books must be chosen from the other 5 books, so the number of forbidden selections is C(5,2) = 10. Subtracting these from the total gives 35 - 10 = 25 valid selections. Therefore option B is correct. Option D is the unrestricted total, while the other values do not correctly remove the selections containing both specified books.

Related tags

BooksRestrictionCombinationsPermutations And CombinationsMathematicsClass 11 Mcq

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