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If (^{12}C_{r}=^{12}C_{r+4}), what is the value of (r)?

Answer and explanation

Correct answer: \(4\)

Use the identity \({}^nC_r={}^nC_{n-r}\). Hence, in \({}^{12}C_r={} ^{12}C_{r+4}\), the two lower indices must be complementary: \(r+4=12-r\). Thus \(2r=8\), so \(r=4\). For example, \(r=5\) would compare \({}^{12}C_5\) and \({}^{12}C_9\), which are not equal because 5 and 9 do not add to 12. Exam tip: for \({}^nC_a={}^nC_b\), usually check whether \(a=b\) or \(a+b=n\).

Related tags

CombinationsNcrSymmetry PropertyBinomial CoefficientsPermutations And CombinationsMathematicsClass 11 Mcq

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