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Among (10) persons, (A) and (B) are special. How many ways can (5) persons be chosen so that exactly one of (A) and (B) is selected?

Answer and explanation

Correct answer: (140)

There are (2) ways to choose the special person and then (4) from the other (8), so (2\binom{8}{4}=140). Exactly one means two symmetric cases.

Related tags

Class11CombinationsExactly-OneRestrictionExpertPermutations And CombinationsMathematicsClass 11 Mcq

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