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Class 11MathematicsPermutations and CombinationsCombinationsExpert
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From the numbers (1) to (20), (3) numbers are chosen so that their sum is odd. How many selections are possible?

Answer and explanation

Correct answer: (570)

For an odd sum, choose (1) odd and (2) even or (3) odd numbers, giving (570). Making a parity case table reduces errors.

Related tags

Class11CombinationsParitySum-OddExpertPermutations And CombinationsMathematicsClass 11 Mcq
सुधार सुझाएँ / Earn

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