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In a set of (10) elements, (a) and (b) are special. How many subsets contain (a) but do not contain (b)?

Answer and explanation

Correct answer: (256)

(a) is fixed as selected and (b) is fixed as not selected, so the remaining (8) elements are free, giving (2^8=256). Fix compulsory states first.

Related tags

Class11CombinationsSubsetsInclude-ExcludeExpertPermutations And CombinationsMathematicsClass 11 Mcq

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