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From (14) objects, (7) are chosen with exactly (3) objects from a fixed group of (5). How many selections are possible?

Answer and explanation

Correct answer: (1260)

Direct answer: Option A, 1,260 selections. The fixed group contains 5 objects, while the remaining outside group contains \(14-5=9\) objects. Exactly 3 objects must come from the fixed group, so choose them in \(\binom{5}{3}=10\) ways. Seven objects are chosen in all, leaving \(7-3=4\) objects to be selected from the 9 outside objects; this gives \(\binom{9}{4}=126\) ways. The multiplication rule gives \(10\times126=1260\). Option A matches. Option B, 1080, option C, 1170, and option D, 1350 do not equal this product, so they count an incorrect number of selections. “Exactly 3” excludes choices containing 0, 1, 2, 4, or 5 objects from the fixed group. The important method is to separate the required group and its complement before applying combinations.

Related tags

Class11CombinationsFixed-GroupExactlyExpert

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