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From the numbers (1) to (15), (4) numbers are chosen so that no two are consecutive. How many selections are possible?(1) से (15) तक की संख्याओं में से (4) संख्याएँ ऐसी चुननी हैं कि कोई दो क्रमागत न हों। कुल चयन कितने हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (495)(495)
The formula gives ( \binom{15-4+1}{4}=\binom{12}{4}=495 ). For no-consecutive selections, take combinations from reduced positions.सूत्र ( \binom{15-4+1}{4}=\binom{12}{4}=495 ) देता है। क्रमागत-वर्जित चयन में घटे हुए स्थानों से संयोजन लें।
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