What is the coefficient of ( x^5 ) in the expansion of ( (1+x)^{12} )?द्विपद प्रसार में ( (1+x)^{12} ) का ( x^5 ) वाला गुणांक कितना है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (792)(792)
The coefficient is ( \binom{12}{5} ), so the answer is (792). In exams, for ( (1+x)^n ), the coefficient of (x^r) is ( \binom{n}{r} ).गुणांक ( \binom{12}{5} ) है, इसलिए उत्तर (792) है। परीक्षा में ( (1+x)^n ) में (x^r) का गुणांक सीधे ( \binom{n}{r} ) लें।
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