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Subjects
Class 11MathematicsPermutations and CombinationsCombinationsHard
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From (14) students a team of (7) is to be formed in which (3) special students are either all included or all excluded. How many ways are there?

Answer and explanation

Correct answer: (660)

If all special students are included there are (\binom{11}{4}=330) ways and if all are excluded there are (\binom{11}{7}=330) ways. The total is (660).

Related tags

CombinationsClass11HardPermutations And CombinationsMathematicsClass 11 Mcq
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