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Class 11MathematicsPermutations and CombinationsCombinationsHard
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From (15) chairs (8) chairs are to be selected and none of (5) broken chairs is selected. How many ways are there?

Answer and explanation

Correct answer: (45)

After removing (5) broken chairs (10) good chairs remain. The ways to choose (8) are (\binom{10}{8}=45).

Related tags

CombinationsClass11HardPermutations And CombinationsMathematicsClass 11 Mcq
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