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From (18) numbers (8) numbers are to be selected with (3) fixed numbers included and (2) fixed numbers excluded. How many ways are there?

Answer and explanation

Correct answer: (1287)

The (3) numbers are fixed and (2) are excluded. The remaining (5) numbers are chosen from (13), so (\binom{13}{5}=1287).

Related tags

CombinationsClass11HardPermutations And CombinationsMathematicsClass 11 Mcq

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