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Subjects
Class 11MathematicsPermutations and CombinationsCombinationsHard
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From (10) white and (11) black balls (7) balls are to be selected such that all balls are not of the same color. How many ways are there?

Answer and explanation

Correct answer: (115830)

Total ways are (\binom{21}{7}=116280). Removing all-white (\binom{10}{7}=120) and all-black (\binom{11}{7}=330) gives (115830).

Related tags

CombinationsClass11HardPermutations And CombinationsMathematicsClass 11 Mcq
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