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From (11) teachers and (13) students a group of (7) people is to be formed with at least (4) teachers. How many ways are there?

Answer and explanation

Correct answer: 136752

The group can contain 4, 5, 6, or 7 teachers. Therefore, the total number of ways is \(\binom{11}{4}\binom{13}{3}+\binom{11}{5}\binom{13}{2}+\binom{11}{6}\binom{13}{1}+\binom{11}{7}\binom{13}{0}\) = \(94380+36036+6006+330=136752\). Hence, 136752 is correct. Option 94380 counts only the case of exactly 4 teachers, not every case covered by “at least 4”. Exam tip: For “at least,” add all cases from the stated number up to the maximum possible number.

Related tags

CombinationsPermutations And CombinationsClass 11At Least ConditionSelection ProblemsMathematicsClass 11 Mcq

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