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From the numbers 1 to 35, how many ways are there to choose 4 odd and 2 even numbers?

Answer and explanation

Correct answer: 416160

The selection is unordered, so combinations are required. Between 1 and 35 inclusive, there are 18 odd numbers and 17 even numbers: the odd numbers are 1, 3, ..., 35, while the evens are 2, 4, ..., 34. Choose four odds in C(18,4) ways and two evens in C(17,2) ways. By the multiplication principle, the total is C(18,4)C(17,2) = 3,060 × 136 = 416,160. Hence option C is correct. Adding the two combination counts would be inappropriate because both choices must be made together; permutations would overcount different orders of the same selected set.

Related tags

CombinationsOdd Even NumbersMultiplication PrinciplePermutations And CombinationsMathematicsClass 11 Mcq

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