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Class 11MathematicsPermutations and CombinationsCombinationsHard
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From (13) colors (6) colors are to be selected. One fixed color must be included, another fixed color must be excluded, and at least one of two other colors must be included. How many ways are there?

Answer and explanation

Correct answer: (336)

One color is fixed and one is excluded. Choose the remaining (5) colors from (11) and subtract (\binom{9}{5}) selections missing both other colors to get (336).

Related tags

CombinationsClass11HardPermutations And CombinationsMathematicsClass 11 Mcq
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