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From (10) boys and (8) girls (7) students are to be selected with exactly (4) girls. How many ways are there?

Answer and explanation

Correct answer: 8400

Exactly 4 girls must be selected, so the remaining 3 students must be boys. The number of ways to choose 4 of the 8 girls is \(\binom{8}{4}=70\), and the number of ways to choose 3 of the 10 boys is \(\binom{10}{3}=120\). Hence, the total number of selections is \(\binom{8}{4}\binom{10}{3}=70\times120=8400\). Option 11760 does not use the required split of 4 girls and 3 boys. Exam tip: when “exactly” is specified, first fix the number chosen from each group and then multiply the combinations.

Related tags

CombinationsPermutations And CombinationsClass 11Selection ProblemsBinomial CoefficientMathematicsClass 11 Mcq

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