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In how many ways can an even number of coins be selected from (14) different coins?

Answer and explanation

Correct answer: 8192

The total number of subsets of 14 distinct coins is \(2^{14}=16384\). Every odd-sized selection can be paired with an even-sized selection by including or removing one fixed coin, so the numbers of even and odd selections are equal. Hence, the number of ways to select an even number of coins is \(\frac{2^{14}}{2}=2^{13}=8192\). \(16384\) counts all selections, not only the even-sized ones. Exam tip: For \(n\geq1\) distinct objects, the number of even-sized subsets and odd-sized subsets is \(2^{n-1}\) each.

Related tags

Permutations And CombinationsCombinationsEven SubsetsClass 11Binomial TheoremMathematicsClass 11 Mcq

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