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How many (6)-element subsets can be formed from (A={1,2,3,4,5,6,7,8,9,10,11,12,13}) that contain (1) and (2) but not (3) and (4)?

Answer and explanation

Correct answer: (126)

The elements (1), (2) are fixed and (3), (4) are excluded. The remaining (4) elements are chosen from (9), so (\binom{9}{4}=126).

Related tags

CombinationsClass11HardPermutations And CombinationsMathematicsClass 11 Mcq

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