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A league has 16 teams and 3 matches are played between every pair of teams. How many matches will be played?

Answer and explanation

Correct answer: 360

The governing concept is combinations because a matchup is determined by selecting two distinct teams, and the order of selection does not matter. The number of unordered pairs among 16 teams is C(16,2) = 16 × 15 ÷ 2 = 120. Every pair plays 3 matches, so multiply the number of pairings by 3: 120 × 3 = 360. Thus option C is correct. If the three matches were ignored, the result would be 120, not any listed answer. Counting ordered pairs would give 240 and would count each pair twice; multiplying that by 3 would overcount the schedule. Options A, B, and D therefore do not satisfy the stated conditions.

Related tags

CombinationsLeague MatchesUnordered PairsPermutations And CombinationsMathematicsClass 11 Mcq

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