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Subjects
Class 11MathematicsPermutations and CombinationsCombinationsHard
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From (13) players (6) players are to be selected. At least (1) and at most (2) of (3) special players are selected. How many ways are there?

Answer and explanation

Correct answer: (1470)

The number of special players can be (1) or (2). The total is (\binom{3}{1}\binom{10}{5}+\binom{3}{2}\binom{10}{4}=1470).

Related tags

CombinationsClass11HardPermutations And CombinationsMathematicsClass 11 Mcq
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