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From (9) teachers and (11) students a group of (6) people is to be formed with at least (3) teachers. How many ways are there?

Answer and explanation

Correct answer: 22260

The group can contain 3, 4, 5, or 6 teachers. Hence, the total number of ways is \(\binom{9}{3}\binom{11}{3}+\binom{9}{4}\binom{11}{2}+\binom{9}{5}\binom{11}{1}+\binom{9}{6}\binom{11}{0}\) = \(13860+6930+1386+84=22260\). Therefore, 22260 is correct. Option 13860 counts only the case of exactly 3 teachers, whereas the question requires at least 3 teachers. Exam tip: For ‘at least’ conditions, add all permitted cases.

Related tags

CombinationsPermutations And CombinationsClass 11Selection ProblemsAt Least ConditionMathematicsClass 11 Mcq

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