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Class 11MathematicsPermutations and CombinationsCombinationsHard
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From (18) students (7) are to be selected so that none of (5) special students is included. How many ways are there?

Answer and explanation

Correct answer: (1716)

After removing (5) special students (13) students remain. Hence there are (\binom{13}{7}=1716) ways.

Related tags

CombinationsClass11HardPermutations And CombinationsMathematicsClass 11 Mcq
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