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Class 11MathematicsPermutations and CombinationsCombinationsHard
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How many (5)-element subsets can be formed from (A={1,2,3,4,5,6,7,8,9,10,11,12}) that contain (1) and (2) but not (3)?

Answer and explanation

Correct answer: (84)

The elements (1) and (2) are fixed and (3) is excluded. The remaining (3) elements are chosen from (9), so (\binom{9}{3}=84).

Related tags

CombinationsClass11HardPermutations And CombinationsMathematicsClass 11 Mcq
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