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From (10) men and (8) women a committee of (6) persons is to be formed with exactly (3) men. How many ways are there?

Answer and explanation

Correct answer: 6720

Since the committee must contain exactly 3 men, the remaining 3 members must be women. The number of ways to choose 3 men from 10 is \(\binom{10}{3}=120\), and the number of ways to choose 3 women from 8 is \(\binom{8}{3}=56\). Therefore, the total number of committees is \(\binom{10}{3}\binom{8}{3}=120\times56=6720\). Option 5040 results from an incorrect count for selecting the women. Exam tip: When “exactly” is specified, choose the required members from each group separately and multiply.

Related tags

CombinationsCommittee SelectionExactly ConditionClass 11 MathematicsPermutations And CombinationsMathematicsClass 11 Mcq

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