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Subjects
Class 11MathematicsPermutations and CombinationsCombinationsHard
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From (15) students (6) students are to be selected. At least (2) of (5) special students must be included. How many ways are there?

Answer and explanation

Correct answer: (3535)

Total ways are (\binom{15}{6}=5005). Removing selections with (0) and (1) special student gives (5005-\binom{10}{6}-\binom{5}{1}\binom{10}{5}=3535).

Related tags

CombinationsClass11HardPermutations And CombinationsMathematicsClass 11 Mcq
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