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From (12) candidates (4) prize winners are to be selected and the prizes are identical. How many ways are there?

Answer and explanation

Correct answer: 495

Since the prizes are identical, the order of the 4 selected candidates does not matter. Therefore, the required number of combinations is
\(\binom{12}{4}=\frac{12!}{4!\,8!}=495\). Option 11880 is \(12P4\), which counts different orders separately, so it is not applicable here. Exam tip: use combinations when a selection is made and the objects are identical.

Related tags

CombinationsPermutations And CombinationsClass 11Identical PrizesSelectionCounting PrinciplesMathematicsClass 11 Mcq

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