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From (10) students a team of (5) is to be formed in which (2) special students are either both included or both excluded. How many ways are there?(10) विद्यार्थियों में से (5) की टीम बनानी है जिसमें (2) विशेष विद्यार्थी दोनों शामिल हों या दोनों बाहर हों। कितने तरीके हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (126)(126)
If both are included there are (\binom{8}{3}=56) ways and if both are excluded there are (\binom{8}{5}=56) ways. The total is (112).दोनों शामिल हों तो (\binom{8}{3}=56) और दोनों बाहर हों तो (\binom{8}{5}=56) तरीके हैं। कुल (56+56=112) है।
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