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Class 11MathematicsPermutations and CombinationsCombinationsMedium
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From (9) chairs (5) chairs are to be selected and none of (3) broken chairs is selected. How many ways are there?

Answer and explanation

Correct answer: (6)

After removing (3) broken chairs (6) good chairs remain. The ways to choose (5) are (\binom{6}{5}=6).

Related tags

CombinationsClass11MediumPermutations And CombinationsMathematicsClass 11 Mcq
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