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Subjects
Class 11MathematicsPermutations and CombinationsCombinationsMedium
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From (9) friends (4) are to be selected for a trip and at least one of two special friends must go. How many ways are there?

Answer and explanation

Correct answer: (91)

Total ways are (\binom{9}{4}=126) and if both special friends do not go then (\binom{7}{4}=35). Hence (126-35=91).

Related tags

CombinationsClass11MediumPermutations And CombinationsMathematicsClass 11 Mcq
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