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From (7) teachers and (9) students a group of (5) people is to be formed with at least (2) teachers. How many ways are there?

Answer and explanation

Correct answer: (3213)

Total ways are (\binom{16}{5}=4368). Removing the cases of (0) teacher and (1) teacher gives (4368-\binom{9}{5}-\binom{7}{1}\binom{9}{4}=3213).

Related tags

CombinationsClass11MediumPermutations And CombinationsMathematicsClass 11 Mcq

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