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From (8) players (3) players are to be selected. One captain is already fixed and must not be selected. How many ways are there?

Answer and explanation

Correct answer: 35

Since the captain is already fixed and must not be included in the selection, only 7 players are available. The number of ways to choose 3 from these 7 players is \(\binom{7}{3}=\frac{7\times6\times5}{3\times2\times1}=35\). Therefore, the correct answer is 35. \(\binom{8}{3}=56\) would apply only if the captain were also available for selection. Exam tip: First subtract anyone who is excluded from the selection.

Related tags

CombinationsPermutations And CombinationsClass 11Team SelectionBinomial CoefficientMathematicsClass 11 Mcq

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