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From (4) red, (5) blue, and (6) green balls, how many ways are there to choose (1) ball of each color?

Answer and explanation

Correct answer: 120

There are 4 choices for the red ball, 5 for the blue ball, and 6 for the green ball. By the multiplication principle, the total number of ways is \(\binom{4}{1}\binom{5}{1}\binom{6}{1}=4\times5\times6=120\). The value 60 can result from multiplying choices for only two colours, so it does not represent the complete selection. Exam tip: When one item is chosen from each independent group, multiply the numbers of choices.

Related tags

CombinationsMultiplication PrincipleClass 11 MathematicsSelecting ObjectsCounting PrinciplePermutations And CombinationsMathematicsClass 11 Mcq

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