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Subjects
Class 11MathematicsPermutations and CombinationsCombinationsMedium
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From (5) white and (6) black balls (4) balls are to be selected such that the colors are not all the same. How many ways are there?

Answer and explanation

Correct answer: (320)

Total ways are (\binom{11}{4}=330). Removing all-white (\binom{5}{4}=5) and all-black (\binom{6}{4}=15) gives (310).

Related tags

CombinationsClass11MediumPermutations And CombinationsMathematicsClass 11 Mcq
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