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From (7) men and (6) women a committee of (5) persons is to be formed with exactly (3) men. How many ways are there?

Answer and explanation

Correct answer: 525

With exactly 3 men, the remaining 2 committee members must be women. The number of ways to choose 3 of the 7 men is \(\binom{7}{3}=35\), and the number of ways to choose 2 of the 6 women is \(\binom{6}{2}=15\). Hence, the total number of committees is \(\binom{7}{3}\binom{6}{2}=35\times15=525\). Using \(\binom{13}{5}\) would be incorrect because it does not enforce the condition of exactly 3 men. Exam tip: when fixed numbers are chosen from separate groups, multiply the respective combinations.

Related tags

CombinationsCommittee SelectionPermutations And CombinationsClass 11Exactly Three MenMathematicsClass 11 Mcq

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