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A committee of (3) persons is to be formed from (8) persons but (2) special persons cannot be selected together. How many ways are possible?

Answer and explanation

Correct answer: (48)

Total ways are (\binom{8}{3}=56) and if both special persons are together the third person is chosen in (6) ways. Hence the valid count is (50).

Related tags

CombinationsClass11MediumPermutations And CombinationsMathematicsClass 11 Mcq

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