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Subjects
Class 11MathematicsPermutations and CombinationsCombinationsMedium
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From (6) red and (5) blue balls (4) balls are to be selected with at least (2) red balls. How many ways are there?

Answer and explanation

Correct answer: (275)

The cases are (2), (3), and (4) red balls. The total is (\binom{6}{2}\binom{5}{2}+\binom{6}{3}\binom{5}{1}+\binom{6}{4}=275).

Related tags

CombinationsClass11MediumPermutations And CombinationsMathematicsClass 11 Mcq
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