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From (8) boys and (6) girls (5) students are to be selected with exactly (2) girls. How many ways are there?

Answer and explanation

Correct answer: 840

After selecting exactly 2 girls, the remaining 3 students must be boys. The number of ways to choose 2 of the 6 girls is \(\binom{6}{2}=15\), and the number of ways to choose 3 of the 8 boys is \(\binom{8}{3}=56\). Hence, the total number of selections is \(\binom{6}{2}\binom{8}{3}=15\times56=840\). Using \(\binom{14}{5}\) would not enforce the condition of exactly 2 girls. Exam tip: When “exactly” is specified, choose the required number from each group separately and multiply.

Related tags

CombinationsPermutations And CombinationsClass 11Selection ProblemsBinomial CoefficientsMathematicsClass 11 Mcq

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