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A team of 4 students is to be formed from 10 students, excluding one particular student. How many teams are possible?

Answer and explanation

Correct answer: 126

The governing concept is restricted combinations. One particular student is excluded, so the eligible population has 10 − 1 = 9 students. A team is an unordered group: rearranging its four members does not produce a new team. Therefore the number of teams is C(9,4) = 9!/(4!5!) = (9×8×7×6)/(4×3×2×1) = 126. Thus option B is correct. The value 210 equals C(10,4), but that incorrectly allows the excluded student. The value 5040 comes from treating the team as an ordered arrangement, which counts each team many times. The value 84 does not equal the required combination, so it has no valid counting basis here.

Related tags

CombinationsTeam SelectionExclusion ConditionClass11Permutations And CombinationsMathematicsClass 11 Mcq

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