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From (10) different photos, (3) photos are to be selected so that two particular photos do not both appear together. How many ways are there?

Answer and explanation

Correct answer: (112)

Total ways are (\binom{10}{3}=120), and ways with both particular photos are (\binom{8}{1}=8). Thus (120-8=112) ways.

Related tags

CombinationsClass11EasyPermutations And CombinationsMathematicsClass 11 Mcq

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