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From (8) different keys, (2) keys are to be selected and one particular key must not be selected. How many ways are there?

Answer and explanation

Correct answer: 21

First exclude the particular key that must not be selected. This leaves 7 keys, and the number of ways to choose 2 of them is \(\binom{7}{2}=\frac{7\times6}{2}=21\). Using \(\binom{8}{2}=28\) would incorrectly include selections containing the prohibited key. Exam tip: for a “must not be selected” condition, remove that object before forming the combination.

Related tags

CombinationsPermutations And CombinationsClass 11Restricted SelectionBinomial CoefficientMathematicsClass 11 Mcq

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