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From (6) English and (5) mathematics books, (3) books are to be selected with no mathematics book. How many ways are there?

Answer and explanation

Correct answer: 20

The condition excludes every mathematics book, so all 3 books must be chosen from the 6 English books. Hence, the number of selections is \(\binom{6}{3}=\frac{6\times5\times4}{3\times2\times1}=20\). Option 15 is \(\binom{6}{2}\), which counts selections of only 2 books. Exam tip: When a category is completely excluded, remove it before forming the combination.

Related tags

CombinationsPermutations And CombinationsClass 11Book SelectionBinomial CoefficientMathematicsClass 11 Mcq

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