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From (15) questions, (5) questions are to be selected, but (3) special questions must not be selected. How many ways are there?

Answer and explanation

Correct answer: 792

The 3 special questions cannot be selected, so they are excluded from the available questions. Thus, 5 questions must be chosen from \(15-3=12\) questions: \(\binom{12}{5}=792\). Therefore, option B is correct. The value 1365 equals \(\binom{15}{4}\), which does not follow the given selection condition. Exam tip: For combinations with forbidden items, first subtract the forbidden items from the total, then apply the combination formula.

Related tags

CombinationsPermutations And CombinationsClass 11Restricted SelectionBinomial CoefficientMathematicsClass 11 Mcq

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