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Subjects
Class 11MathematicsPermutations and CombinationsCombinationsEasy
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From (10) players, (5) are to be selected and two special players should not be selected together. How many ways are there?

Answer and explanation

Correct answer: (224)

Total ways are (\binom{10}{5}=252), and ways with both special players are (\binom{8}{3}=56). Thus the valid ways are (196).

Related tags

CombinationsClass11EasyPermutations And CombinationsMathematicsClass 11 Mcq
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